Chemistry — Buffers
Henderson–Hasselbalch in acid and base forms; buffer range.
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\text{pH} = \text{p}K_a + \log\frac{[\text{A}^-]}{[\text{HA}]}
\text{pOH} = \text{p}K_b + \log\frac{[\text{BH}^+]}{[\text{B}]}
K_a = \frac{[\text{H}^+][\text{A}^-]}{[\text{HA}]}
\text{buffer range} = \text{p}K_a \pm 1