Chemistry — Combustion Analysis

\text{mass C} = \text{mass CO}_2 \times \tfrac{12}{44}

\text{mass H} = \text{mass H}_2\text{O} \times \tfrac{2}{18}

\text{mass O} = \text{total} - (\text{C} + \text{H})

\text{mole ratio} \rightarrow \text{empirical formula}