Chemistry — Integrated Rate Laws

\text{zero order:}\quad [A]_t = [A]_0 - kt

\text{first order:}\quad \ln[A]_t = \ln[A]_0 - kt

\text{second order:}\quad \frac{1}{[A]_t} = \frac{1}{[A]_0} + kt

t_{1/2}\ \text{(1st)} = \frac{\ln 2}{k}