Chemistry — Integrated Rate Laws

[\text{A}] = [\text{A}]_0 - kt \;\;\text{(zero order)}

\ln[\text{A}] = \ln[\text{A}]_0 - kt \;\;\text{(first order)}

\frac{1}{[\text{A}]} = \frac{1}{[\text{A}]_0} + kt \;\;\text{(second order)}

t_{1/2} = \frac{\ln 2}{k}\;\;\text{(first order)}