Physics — Otto Cycle (Air-Standard, Worked)
The four-process Otto cycle with every state point computed from r = 10 and γ = 1.40: pressures, temperatures, heat in and out, net work and a 60.2 % air-standard efficiency.
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"label": "Isentropic relations do the work: T₂/T₁ = r^(γ−1) = 10^0.4 = 2.512 and P₂/P₁ = r^γ = 10^1.4 = 25.12.",
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"label": "② end of compression · 754 K · 2.51 MPa · V₁/10",
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"label": "③ end of combustion · 1868 K · 6.23 MPa · V₃ = V₂",
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"label": "T₃ = T₂ + q_in/c_v = 754 + 800/0.718 = 1868 K. At constant volume P₃ = P₂ × T₃/T₂ = 6.23 MPa.",
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"label": "w_net = q_in − q_out = 800 − 318 = 482 kJ kg⁻¹",
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{
"id": "ot-params",
"type": "note",
"label": "Compression ratio r = V₁/V₂ = 10 · γ = 1.40 · c_v = 0.718 kJ kg⁻¹ K⁻¹ · working fluid treated as air throughout.",
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"id": "ot-eta",
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"label": "η = 1 − r^(1−γ) = 1 − 10^(−0.4) = 60.2 %",
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"label": "① intake valve closed · 300 K · 100 kPa · V₁",
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"label": "④ end of expansion · 744 K · 248 kPa · V₄ = V₁",
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"id": "ot-assume",
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"label": "Air-standard cold-air assumptions: air as an ideal gas with constant specific heats, combustion replaced by external heat addition, no friction and no heat loss through the walls.",
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"id": "ot-strokes",
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"label": "Four processes, not four strokes: the intake and exhaust strokes are constant-pressure legs that cancel in the idealisation, leaving compression, ignition, power and blow-down.",
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{
"id": "ot-real",
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"label": "Real petrol engines manage 25–35 % brake thermal efficiency. Knock caps r at about 10–12, combustion is neither instantaneous nor at constant volume, and the walls leak heat.",
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"target": "ot-s2",
"label": "1→2 isentropic compression, work in"
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{
"id": "ot-e3",
"source": "ot-qin",
"target": "ot-s3",
"label": "2→3 constant-volume heat addition"
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{
"id": "ot-e4",
"source": "ot-s3",
"target": "ot-s4",
"label": "3→4 isentropic expansion, the power stroke"
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{
"id": "ot-e5",
"source": "ot-s4",
"target": "ot-qout"
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"id": "ot-e6",
"source": "ot-qout",
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"label": "4→1 constant-volume heat rejection"
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"label": "η = w_net / q_in",
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